Q12 of 50 Page 1

A reaction is of second order with respect to a reactant. How is the rate of reaction affected if the concentration of the reactant is reduced to half? What is the unit of rate constant for such a reaction?

If a reaction is of second order then,



So, rate equation stands as


Rate = k[A]2


here k is rate constant


So, according to the rate equation,


If concentration of A is halved, Rate becomes one-fourth times.
(Putting the concentration of A = 0.5 in the rate equation)


If the reaction is second order, then two units of concentration are already present so the rate constant needs reciprocal time plus inverse units of concentration, L mol-1 s-1.


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