What is the acceleration due to gravity on the top of Mount Everest? Mount Everest is the highest mountain peak of the world at the height of 8848 m. The value at sea level is 9.80 ms^-2.

The gravitational field in a region is given by E = (2i + 3j)Nkg^-1. Show that no work is done by the gravitational field whom a particle is moved on the line 3y +2x = 5.

[Hint: if a line y=mx + c makes angle θ with the X – axis, m= tan θ]

Find the height over the earth’s surface at which the weight of a body becomes half of its value at the surface.

Find the acceleration due to gravity in a mine of depth 640 m if the value at the surface is 9.800 ms^-2. The radius of the earth is 6400 Km.

A body is weighed by a spring balance to be 1.000 kg at the North Pole. How much will it weigh at the equator? Accounts for the earth’s rotation only.