Consider the situation of the previous problem. Let the water push the left wall by a force F₁ and the right wall by a force F₂.

A wooden object floats in water kept in a beaker. The object is near a side of the beaker (figure 13-Q4). Let P₁, P₂, P₃ be the pressures at the three points A, B and C of the bottom as shown in the figure.

A closed cubical box is completely filled with water and is accelerated horizontally towards right with an acceleration a. The resultant normal force by the water on the top of the box

Water enters through end A with a speed u₁ and leaves through end B with a speed u₂ of a cylindrical tube AB. The tube is always completely filled with water. In case I the tube is horizontal, in case II it is vertical with the end A upward and in case III it is vertical with the end B upward. We have v₁ = v₂ for

Bernoulli theorem is based on conservation of