The near point of the eye of a person is 50 cm. Find the nature and power of the corrective lens required by the person to enable him to see clearly the objects placed at 25 cm. from the eye.
According to the question
Object Distance (u) = -25 cm
Image Distance (v) = -50 cm
By Lens Formula
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⇒ ![]()
⇒ ![]()
⇒ F = 50 cm.
Since focal length is positive hence the lens is convex lens.
Power = ![]()
Focal length = 50 cm = 0.5 m
1 m = 100 cm.
⇒ Power =![]()
Hence the Power is 2 Dioptre
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