Q10 of 43 Page 226

In the following figures, find the area of the shaded portions:

(i) We have to find out the Area of (EFDC):


Area of EFDC = Area of ABCD – Area of BCE – Area of AFE




= 180 – 40 – 30


= 180 – 70


= 110 cm2


(ii) We have to find out the Area of QTU:


Area of QTU = Area of PQRS – Area of TSU – Area of RUQ – Area of PQT



= 400 – 50 – 100 – 100


= 400 – 250


= 150 cm2


More from this chapter

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7

Through a rectangular field of length 90 m and breadth 60 m, two roads are constructed which are parallel to the sides and cut each other at right angles through the center of the field. If the width of each road is 3 m,

Find:


(i) The area covered by the roads.


(ii) The cost of constructing the roads at the rate of Rs. 110 per m2.

 8

Pragya wrapped a cord around a circular pipe of radius 4 cm (adjoining figure) and cut off the length required of the cord. Then she wrapped it around a square box of side 4 cm (also shown). Did she have any cord left?


 9

The adjoining figure represents a rectangular lawn with a circular flower bed in the middle.

Find:


(i) The area of the whole land


(ii) The area of the flower bed


(iii) The area of the lawn excluding the area of the flower bed


(iv) The circumference of the flower bed.


 11

Find the area of the quadrilateral ABCD.

Here, AC = 22 cm,


BM = 3 cm,


DN = 3 cm, and


BM AC, DNAC