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8. Linear Equations
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Q5 of 90 Page 107

Solve:


By cross multiplication


⇒


Taking LCM of 5 and 1 = 5 on LHS



⇒ 2y = - 5 × 4


⇒ y = - 5 × 2 = - 10


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Questions · 90
8. Linear Equations
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