Q9 of 90 Page 111

Find three consecutive odd numbers whose sum is 147. Hint. Let the required numbers be (2x + 1), (2x + 3) and (2x + 5).

Let the numbers be (2x + 1), (2x + 3) and (2x + 5)


According to the question


2x + 1 + 2x + 3 + 2x + 5 = 147


By cross multiplication


⇒ 6x + 9 = 147


⇒ 6x = 147 - 9



So the numbers are (2x + 1) = 47, (2x + 3) = 49 and (2x + 5) = 51


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