Solve:
Taking LCM of 5 and 2 = 10 on LHS and LCM of 3 and 1 = 3 on RHS
By cross multiplication
⇒ 3(4x + 14 - 15x - 55) = 10(2x - 7)
⇒ 3( - 11x - 41) = 20x - 70
⇒ - 33x - 20x = 123 - 70
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