Q10 of 34 Page 252

Factorize: (7a3 + 56b3)

(7a3 + 56b3)

= 7(a3 + 8b3)


= 7(a3 + (2b)3)


= 7(a + (2b))(a2 + (2b)2 - a(2b))


[since a3 + b3 = (a + b)(a2 + b2 - ab)]


= 7(a + 2b)(a2 + 4b2 - 2ab)


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