Q34 of 34 Page 252

In the given figure, AB || CD If ∠BAE = 100° and ∠ECD = 120° then x = ?

Draw one line EF || CD and AB.

Since EF || CD and CE is transversal.


∠FEC + ∠ECD = 180°


∠FEC = 60° {since ∠ECD = 120°}


Also, EF || AB and AE is transversal.


∠FEA + ∠BAE = 180°


∠FEA = 80° {since ∠BAE = 100°}


And x = ∠FEC + ∠FEA


= 60° + 80°


= 140°


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