Q13 of 34 Page 252

In a ΔABC if 2∠A = 3∠B = 6∠C, calculate the measure of ∠B.

In a triangle sum of all angles = 180°

So, ∠A + ∠B + ∠C = 180°


It is given that-


∠A = 3/2 ∠B


∠C = � ∠B


So, ∠A + ∠B + ∠C = (3/2) ∠B + ∠B + (1/2) ∠B = 180°


3∠B = 180°


∠B = 60°


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