Q10 of 57 Page 60

If in ∆ABC and ∆DEF, then they will be similar, when

Given,

∆ABC and ∆EDF,


→ AB/DE = BC/FD



By converse of basic proportionality theorem, that if a line divides any two sides of a triangle in the same ratio, then the line must be parallel to the third side.


As we have,


∆ABC ∼ ∆EDF


Then,


∠B = ∠D,


∠A = ∠E and,


∠C = ∠F

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