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6. Triangles
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Q4 of 57 Page 63

In figure, BD and CE intersect each other at the point P. Is ∆PBC ∼ ∆PDE?

Why?


(True)

In ∆PBC and ∆PDE,


∠BPC = ∠EPD [vertically opposite angles]



Since, ∠BPC of ∆PBC is equal to ∠EPD of ∆PDE and the sides including these.


So,


∆PBC ∼ ∆PDE by SAS similarity criteria.


More from this chapter

All 57 →
2

It is given that ∆DEF ∼ ∆RPQ. Is it true to say that ∠D = ∠R and ∠F = ∠P? Why?

3

A and B are respectively the points on the sides PQ and PR of a ∆PQR such that PQ = 12.5 cm, PA = 5 cm, BR = 6 cm and PB = 4 cm, Is AB || QR? Give reason for your answer.

5

In ∆PQR and ∆MST, ∠P = 55°, ∠Q = 25°, ∠M = 100° and ∠S = 25°. Is ∆QPR ∼ ∆TSM? Why? (True)

6

Is the following statement true? Why? ‘‘Two quadrilaterals are similar, if their corresponding angles are equal’’.

Questions · 57
6. Triangles
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