Q11 of 57 Page 60

If ∆ABC ∼ ∆QRP, AB = 18 cm and BC = 15 cm, then PR is equals to,

Given,

∆ABC ∼ ∆QRP


AB = 18 cm and


BC = 15 cm



By Similar triangles area property, the ratio of area of two similar triangles is equal to the ratio of square of their corresponding sides.


So,


We have,



(By similar triangles area property).


But given



∴ RP = √100 = 10 cm

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