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1. Real Numbers
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Q6 of 114 Page 10

Is it possible to have two numbers whose HCF is 18 and LCM is 760? Give reason.

No, ∵ HCF does not divided LCM exactly


Using Euclid’s division lemma -


Take a = 760 and b = 18.


a = bq + r. where q is the quotient, r is the remainder and b is the divisor.


If HCF divides LCM completely, r = 0.


Putting the values -


Here 760 = 18(42) + 4


⇒ r = 4


∵ r is not equal to zero


∴ HCF does not divides LCM completely.


So this is not possible for two numbers to have HCF = 18 and LCM = 760.


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4

The HCF of two numbers is 145 and their LCM is 2175. If one of the numbers is 725, find the other.

5

The HCF of two numbers is 18 and their product is 12960.Find their LCM.

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8

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Questions · 114
1. Real Numbers
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