Q17 of 114 Page 36

The LCM of two numbers is 1200. Show that the HCF of these numbers cannot be 500. Why?

No, HCF should divide LCM exactly.

Using Euclid’s division lemma -


Take a = 1200 and b = 500.


a = bq + r. where q is the quotient, r is the remainder and b is the divisor.


If HCF divides LCM completely, r = 0.


Here 1200 = 500(2) + 200


r = 200


r is not equal to zero.


HCF does not divides LCM completely.


So this is not possible for two numbers to have HCF = 500 and LCM = 1200.


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