Q5 of 45 Page 474

Construct an equilateral triangle each of whose altitudes measures 5.4 cm.

Steps of Construction


1. Draw a line XY.


2. Mark any point P on it.


3. From P, draw PQ ⊥ XY.



4. From P, set off PA= 5.4 cm cutting PQ at A.


5. Construct ∠PAC=∠ PAB =30°, meeting XY at B and C respectively.


Capture.PNG


Therefore, ΔABC is required equilateral triangle.


More from this chapter

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3

Construct an angle of 90° and draw its bisector.

 4

Construct an equilateral triangle each of whose sides measures 5 cm.

 6

Construct a ΔABC in which BC = 5 cm, AB = 3.8 cm and AC = 2.6 cm.

 7

Construct a ΔABC in which BC = 4.7 cm, ∠B = 60° and ∠C = 30°. Measure ∠A.