Q15 of 45 Page 476

Construct a ΔABC in which base BC = 5.2 cm, ∠B = 60° and (AB + AC) = 7.6 cm.

Steps of Construction


1. Draw BC = 5.2 cm


2. Construct ∠CBX=60°


3. Along BX set off BP = 7.6 cm


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4. Join CP.


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5. Draw the perpendicular bisector of CP to intersecting BP at A.


6. Join AC.



Therefore, ΔABC is the required triangle.


More from this chapter

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Draw a line segment AB of length 5.2 cm and construct the perpendicular bisector of AB.

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Construct an angle of 60° and bisect it.

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Construct a square each of whose sides measures 3.2 cm.

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Construct a ΔABC in which base BC = 4.8 cm, ∠B = 45° and (AB – AC) = 2.5 cm.