Q17 of 45 Page 476

Construct a ΔABC in which base BC = 4.8 cm, ∠B = 45° and (AB – AC) = 2.5 cm.

Steps of Construction


1. Draw BC= 4.8 cm


2. Construct ∠CBX=45°


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3. Along BX set off BP = 2.5 cm


4. Join PC



5. Draw the perpendicular bisector of PC meeting BP produced at A.


6. Join AC.


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Therefore, ΔABC is the required triangle.


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