Q5 of 30 Page 621

Construct a ΔABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are 3/4 times the corresponding sides of ΔABC.

Steps of Construction:


 


1. First, we draw a triangle ABC of given dimensions.


 


2. Draw a line segment BC of length 7cm.


 


3. From B, make an angle of 60° and draw a ray from B.


 



 


4. Now taking B as center and radius of 6cm(length of AB), draw an arc on the ray. The point is A.


 


5. Join AC.


 



 


6. Now we have to make a triangle which is 3/4 times of this triangle.


 


7. Draw a ray BZ making an acute angle with the line BC. Make 4 equal arcs starting from B then B1 and so on till B4.


 



 


8. Join B4C. Draw a line from B3 parallel to B4C cutting BC at C’.


 



 


9. Draw another line from C’ parallel to CA cutting AB at A’.


 



 


10. A’BC’ is our required triangle,


 

More from this chapter

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3

Construct a ΔPQR, in which PQ = 6 cm, QR = 7 cm and PR = 8 cm. Then, construct another triangle whose sides are 4/5 times the corresponding sides of ΔPQR.

 4

Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are 7/5 of the corresponding sides of the first triangle.

 6

Construct a ΔABC in which AB = 6 cm, ∠A = 30° and ∠B = 60°. Construct another ΔAB' C' similar to ΔABC with base AB' = 8 an.

 7

Construct a ΔABC in which BC = 8 cm, ∠B = 45° and ∠C = 60°. Construct another triangle similar to ΔABC such that its sides are 3/5 of the corresponding sides of ΔABC.