Q7 of 30 Page 621

Construct a ΔABC in which BC = 8 cm, ∠B = 45° and ∠C = 60°. Construct another triangle similar to ΔABC such that its sides are 3/5 of the corresponding sides of ΔABC.

Steps of Construction:


1. Draw a line segment BC of length 8cm.


2. Make an angle of 45° from B and an angle of 60° from C. The point where the rays meet is point A.



3. Draw a ray BY making an acute angle with the line BC. Make 5 equal arcs starting from B, then B1 and so on till B5.



4. Join B5C.



5. As we have to get the triangle 3/5 times of this triangle ABC.


6. From B3, draw a line parallel to B5C cutting BC at C’.



7. Draw another line from C’ parallel to AC cutting AB at A’.



8. A’BC’ is our required triangle.


More from this chapter

All 30 →
5

Construct a ΔABC with BC = 7 cm, ∠B = 60° and AB = 6 cm. Construct another triangle whose sides are 3/4 times the corresponding sides of ΔABC.

 6

Construct a ΔABC in which AB = 6 cm, ∠A = 30° and ∠B = 60°. Construct another ΔAB' C' similar to ΔABC with base AB' = 8 an.

 8

To construct a triangle similar to ΔABC in which BC = 4. 5 cm, ∠B = 45° and ∠C = 60°, using a scale factor of 3/7, BC will be divided in the ratio

(a) 3 : 4 (b) 4:7


(c) 3 : 10 (d) 3 : 7

 9

Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another triangle whose sides are times the corresponding sides of the isosceles triangle.