Construct a ΔABC in which BC = 6. 5 cm, AB = 4. 5 cm and ∠ABC = 60°. Construct a triangle similar to this triangle whose sides are 3/4 of the corresponding sides of ∠ABC.

Steps of Construction:

1. First we draw a triangle ABC of given dimensions.

2. Draw a line segment BC of length 6. 5 cm.

3. From B, make an angle of 60° and draw a ray from B.

4. Now taking B as center and radius of 4. 5 cm (length of AB), draw an arc on the ray. The point is A.

5. Join AC.

6. Now we have to make a triangle which is 3/4 times of this triangle.

7. Draw a ray BZ making an acute angle with the line BC. Make 4 equal arcs starting from B then B1 and so on till B4.

8. Join B4C. Draw a line from B3 parallel to B4C cutting BC at C’.

9. Draw another line from C’ parallel to CA cutting AB at A’.

11. A’BC’ is our required triangle.