Construct a right triangle in which the sides, (other than the hypotenuse) are of length 6 cm and 8 cm. Then construct another triangle, whose sides are times the corresponding sides of the given triangle.

To construct a right-angled triangle such that its sides are 3/5 times of the corresponding sides of the given triangle:

(a). Draw a line AB = 8 cm as a base.

(b). Draw another line BC = 6 cm perpendicular to AB.

(c). Connect A to C as the hypotenuse.

Now we shall construct another triangle whose sides are 3/5 times the corresponding sides of the triangle.

(d). Set the compass to 1 cm, rest one of the legs of the compass at point A and start making arcs A₁ starting from A, A₂ from A₁, A₃ from A₂ and so on till A₅, since we have to construct a triangle having side equal to 3/5 times of corresponding sides of the given triangle.

(e). Join A₅ to B.

(f). Now, draw a line to AB from A₃, parallel to BA₅.

(g). Say this point on AB is B’.

(h). Similarly, cut marks from B’ perpendicular to AB. We get B’C’.

(i). We get AC’ automatically.

And hence, we have the required triangle AB’C’.