Q8 of 33 Page 14

Find the value of p, if the mean of the following distribution is 20. 

x 15 17 19 20 + p 23
f 2 3 4 5p 6

 








xifixfi
15230
17351
19476
20 + p5p100p + 5p2
236138
Total15 + 5p5p2+100p + 295

Mean = =
20 =
5p2+100p + 295 = 300 + 100p
            5p2 - 5 = 0
          5(p2 - 1) = 0
   (p + 1)(p - 1) = 0
       p = 1 or p = -1

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