Q17 of 33 Page 14

Find the missing frequencies and the median for the following distribution if the mean is 1.46.


Given, N = 200


= 46 + x + y + 25 + 10 + 5 = 200


= x + y = 200 – 46 – 25 – 10 – 5


= x + y = 114 (i)


And Mean = 1.46





= x + 2y + 140 = 292


= x + 2y = 292 – 140


= x + 2y = 152 (ii)


Subtract (i) from (ii), we get


X + 2y – x – y = 152 – 114


y = 38


Put the value of y in (i), we get


x = 114 – 38 = 76



We have, N = 200



= 100


The cumulative frequency just more than is 122 so the median is 1.


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