How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming (i) repetition of digits allowed. (ii) repetition of digits now allowed?
How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming (i) repetition of digits allowed. (ii) repetition of digits now allowed?
Number of digits given = 5
(i) Since repetition is allowed,
units place can be filled in 5 ways
similarly, tens place can be filled in 5 ways
hundreds place can be filled in 5 ways
Therefore, no. of 3 digit numbers when repetition allowed = 5 x 5 x 5 = 125
(ii) Since repetition is not allowed,
units place can be filled in 5 ways
tens place can be filled in 4 ways
hundreds place can be filled in 3 ways
Therefore, no. of 3 digit numbers when repetition is not allowed = 5 x 4 x 3 = 60
AI is thinking…
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.