Q22 of 30 Page 7

(iii) There are always 4 letters between P and S.

(i) ‘PERMUTATIONS’ is a 12-letter word.

If the first letter and last letter are fixed as P and S the remaining 10 places will be filled in following way:

The number of repeated letters is: T repeated 2 times.

Therefore possible number of ways is: =

= 1814400

(ii) Vowels are all together

When the vowels are together, these 5 letters will form a place in the word together.

Therefore the number of words will be =
==2419200

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