The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs. 18. Find the missing frequency k.


We know the formula of mean is given by,
Mean = ![]()
Substituting mean = 18, ∑fixi = 704 + 20k & ∑fi = 40 + k in the above equation, we get
18 = ![]()
⇒ 18 (40 + k) = 704 + 20k
⇒ 720 + 18k = 704 + 20k
⇒ 20k – 18k = 720 – 704
⇒ 2k = 16
⇒ k = 16/2
⇒ k = 8
Thus, k = 8.
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