Q4 of 59 Page 70

Solve the following equations.

Given:


We first put x = 0 in the expression and obtain:



63/12 = 3/(-5) which does not hold true.


x=0 is not a solution.


Now, let ……………… (1)


Multiply numerator and denominator of second expression by 5x:





……………….(2)


From equation (1) and (2), we get:



Cross multiply and obtain:


8x + 12 = 21x – 105


21x 8x = 12 + 105


13x = 107


x = 9


x=2 is the solution.


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