Solve the following equations.

Given: ![]()
We first put x = 0 in the expression and obtain:
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⇒ 63/12 = 3/(-5) which does not hold true.
∴ x=0 is not a solution.
Now, let
……………… (1)
Multiply numerator and denominator of second expression by 5x:
![]()
![]()
![]()
……………….(2)
∴ From equation (1) and (2), we get:
![]()
Cross multiply and obtain:
8x + 12 = 21x – 105
⇒ 21x – 8x = 12 + 105
⇒13x = 107
⇒ x = 9
∴ x=2 is the solution.
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