Find the distances with the help of the number line given below.

i. d(B, E)

ii. d(j, A)

iii. d(P, C)

iv. d(J, H)

v. d(K, O)

vi. d(O, E)

vii. d(Q, B)

To find the distance between two points, consider their co-ordinates and subtract smaller co-ordinate from the larger.

(i) Now, the co-ordinates of B and E are 2 and 5 respectively. We know that 5 > 2.

So, d (B, E) = 5 – 2 = 3

⇒ d (B, E) = 3

(ii) The co-ordinates of J and A are -2 and 1 respectively. We know that 1 > -2.

So, d (J, A) = 1 – (-2) = 1 + 2 = 3

⇒ d (J, A) = 3

(iii) The co-ordinates of P and C are -4 and 3 respectively. We know that 3 > -4.

So, d (P, C) = 3 – (-4) = 3 + 4 = 7

⇒ d (P, C) = 7

(iv) The co-ordinates of J and H are -2 and -1 respectively. We know that -1 > -2.

So, d (J, H) = (-1) – (-2) = -1 + 2 = 1

⇒ d (J, H) = 1

(v) The co-ordinates of K and O are -3 and 0 respectively. We know that 0 > -3.

So, d (K, O) = 0 – (-3) = 0 + 3 = 3

⇒ d (K, O) = 3

(vi) The co-ordinates of O and E are 0 and 5 respectively. We know that 5 > 0.

So, d (O, E) = 5 – 0 = 5

⇒ d (O, E) = 5

(vii) The co-ordinates of P and J are -4 and -2 respectively. We know that -2 > -4.

So, d (P, J) = (-2) – (-4) = -2 + 4 = 2

⇒ d (P, J) = 2

(viii) The co-ordinates of Q and B are -5 and 2 respectively. We know that 2 > -5.

So, d (Q, B) = 2 – (-5) = 2 + 5 = 7

⇒ d (Q, B) = 7