Q2 of 45 Page 27

In ΔPQR, ∠P = 70° ∠Q = 65° then find ∠R.

Given, ∠P = 70° ∠Q = 65°


In a triangle we know sum of interior angles is 180°


∴ in ΔPQR


∠P + ∠Q + ∠R = 180°


70° + 65° + ∠R = 180°


∠R = 180° - 135° = 45°


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