In figure 3.25, ∠P ≅ ∠R seg PQ ≅ seg RQ
Prove that, ΔPQT ≅ ΔPQS

In ΔPQT and ΔRQS
∠P = ∠R …………[Given]
∠QPT = ∠QRS
PQ = RQ ………….[Given]
∠PQT = ∠RQS ………….[common]
∴ By ASA congruency
ΔPQT ≅ ΔRQS
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