Solve the following examples.
The speed of sound in air at 00C is 332 m/s. If it increases at the rate of 0.6 m/s per degree, what will be the temperature when the velocity has increased to 344 m/s?
Given:
Speed of sound in air at 00C = 332m/s
Speed increases at a rate of 0.6m/s per degree
Temperature at 344 m/s = T0c
Difference in velocities = 344 m/s - 332 m/s
= 12 m/s
Increase in temperature corresponding to the increase in velocity =
12/0.6 = 200C
Therefore temperature at velocity 344m/s = 00C + 200C = 200C
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