Q5 of 12 Page 137

Solve the following examples.

Nita heard the sound of lightning after 4 seconds of seeing it. What was the distance of the lightning from her?

Given:

Velocity of sound in air (v) = 340 m/s2


Time taken for the sound to reach the receiver(t) = 4 sec


Distance of the source from receiver (d) = v × t


= 340 × 4


= 1360 m/s


More from this chapter

All 12 →
4

Where and why are sound absorbing materials used?

 5

Solve the following examples.

The speed of sound in air at 00C is 332 m/s. If it increases at the rate of 0.6 m/s per degree, what will be the temperature when the velocity has increased to 344 m/s?

 5

Solve the following examples.

Sunil is standing between two walls. The wall closest to him is at a distance of 360 m. If he shouts, he hears the first echo after 4 s and another after another 2 seconds.


1. What is the velocity of sound in air?


2. What is the distance between the two walls?

 5

Solve the following examples.

Hydrogen gas is filled in two identical bottles, A and B, at the same temperature. The mass of hydrogen in the two bottles is 12gm and 48 gm respectively. In which bottle will sound travel faster? How many times as fast as the other?