Construct Δ ABC, in which BC = 6cm, ∠ABC = 100° and AC – AB – 2.5CM

Given: Base BC = 6cm, AC-AB = 2.5cm and

∠B = 100° of Δ ABC.

Required: To construct a triangle ABC.

Steps of construction:

i: Draw a segment BC of length 6cm.

ii: Draw ray BT such that ∠B = 100°

iii: Mark an arc on opposite of ray BT i.e. ray BS cutting at D such that BD = 2.5cm.

iv: Draw segment CD.

v: Construct the perpendicular bisector of segment CD.

vi: Name the point of intersection of ray BS and the perpendicular bisector of CD as A.

vii: Draw segment AC.

ΔABC is the required triangle.