Construct Δ PQR, in which ∠Q =70°, ∠R = 80° and PQ+QR+PR=9.5cm

Given: ∠Q =70°,

∠R = 80° and

perimeter of Δ PQR

Steps of construction:

i: Draw a line segment XY of 9.5cm.

ii: From point X draw a ray XD at 70° and from Y draw a ray YE at 80°.

iii: Draw an angle bisector of X and Y, two angle bisectors intersect each other at point A.

iv: Draw a line bisector of XA and AY respectively these two-line bisectors intersect at point B and C.

v: Join AB and AC.

vi: Δ ABC is required triangle.