Construct Δ ABC, in which ∠B =70°, ∠C = 60°, AB+BC+AC=11.2cm.

Given: ∠B =70°, ∠C = 60° and perimeter of Δ ABC

Steps of construction:

i: Draw a line segment PQ of 11.2cm.

ii: From point P draw a ray PD at 70° and from Q draw a ray QE at 60°

iii: Draw an angle bisector of P and Q, two angle bisectors intersect each other at point A.

iv: Draw a line bisector of AP and AQ respectively these two-line bisectors intersect at point B and C

v: Join AB AND AC

vi: Δ ABC is required triangle.