Solve any two sub-questions:
Prove that “The length of the two tangent segments to a circle drawn from an external point are equal.”
The figure is as follows:

Given:
A circle with centre O, an external point P of the circle. The two tangents through the point P touches the circle at the points A and B.
To prove that PA = PB
Construction:
Draw the segment OA, segment OB and segment OP.
Proof:
∠ PAO = ∠ PBO ... (Radius is perpendicular to tangent)
In the right angled ∆ PAO and the right angled ∆PBO.
Segment OA ≅ segment OB ... (Radii of same circle)
Hypotenuse PO ≅ hypotenuse PO ... (common side)
∆ PAO ≅ ∆ PBO ... (Hypotenuse side theorem)
∴ Segment PA ≅ segment PB ... (c.s.c.t)
∴ PA = PB
Hence Proved.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.

