Q2 of 23 Page 1

Attempt any four sub-questions from the following:

Find the first four terms in an A.P. When a = 10 and d = 3.

Given, a = 10 and d = 3

Let Tn be nth term of A.P.


Tn = a + (n – 1)d


T1 is the first term, T2 is the second term, T3 is the third term and T4 is the fourth term.


T1 = 10 + (1 – 1) × 3 = 10 + 0 × 3


∴ T1 = 10


T2 = 10 + (2 – 1) × 3 = 10 + 1 × 3 = 10 + 3


∴ T2 = 13


T3 = 10 + (3 – 1) × 3 = 10 + 2 × 3 = 10 + 6


∴ T3 = 16


T4 = 10 + (4 – 1) × 3 = 10 + 3 × 3 = 10 + 9


∴ T4 = 19


First four terms of A.P. is 10, 13, 16 and 19.


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