Attempt any two sub-questions from the following:
Solve the following simultaneous equations: 27/(x-2) + 31/(y+3) = 85; 31/(x-2) + 27/(y+3) = 89.
Given equations are 27/(x-2) + 31/(y+3) = 85; 31/(x-2) + 27/(y+3) = 89.
Let 1/(x-2) = a and 1/(y+3) = b
Given equations becomes
27a + 31b = 85 ………………..(1)
31a + 27b = 89 ………………..(2)
Adding (1) and (2)
27a + 31b + 31a + 27b = 85 + 89
⇒ 58a + 58b = 174
⇒ 58 (a + b) = 174
⇒ a + b = 3 …………………(3)
Subtracting equation (1) and (2)
27a + 31b – 31a – 27b = 89
⇒ -4a + 4b = -4
⇒ a – b = 1 …………………(4)
Adding equation (3) and (4)
a + b + a – b = 4
⇒ 2a = 4
⇒ a = 4/2
⇒ a = 2
Putting value of a in (4)
2 – b = 1
⇒ b = 2 – 1
⇒ b = 1
Resubstituting
a = 1/(x – 2)
⇒ 1/(x – 2) = 2
⇒ 1 = 2x – 4
⇒ 2x = 1 + 4
⇒ x = 5/2
b = 1/(y + 3)
⇒ 1 = 1/(y + 3)
⇒ y + 3 = 1
⇒ y = 1 – 3
⇒ y = -2
∴ x = 5/2 and y = -2
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