Find the length of the diagonal of a square with side 8 cm.

In ∆ABC, AB = 8cm, BC = 8cm ∠B = 90°
By Pythagoras theorem
AC2 = AB2 + BC2
= (8)2 + (8)2
= 64 + 64
= 128
Hence, AC2 = 128
∴ AC = ![]()
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