Q1 of 23 Page 1

Solve any five sub-questions:

In the following figure RP: PK = 3 : 2, then find the value of A(ΔTRP) : A(ΔTPK).


Extend the segment RK to line l and draw perpendicular from point T to the line l at M as shown in the figure


TM becomes height of ∆TRP and ∆TPK



Area of triangle = (1/2) × base × height


A(∆TRP) = (1/2) × RP × TM


A(∆TPK) = (1/2) × PK × TM



using (i)



Hence A(∆TRP): A(∆TPK) = 3:2


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