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July-2017
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Q3 of 23 Page 1

Solve any the three sub-questions:

Prove that: sec2θ + cosec2θ = sec2θ x cosec2θ.

LHS = sec2θ + cosec2θ


by squaring we get




We know that sin2θ + cos2θ = 1



∴ LHS = sec2θ × cosec2θ


= RHS


∴ sec2θ + cosec2θ = sec2θ × cosec2θ


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Questions · 23
July-2017
1 1 1 1 1 1 2 2 2 2 2 2 3 3 3 3 3 4 4 4 5 5 5
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