Solve the following equation.
On cross multiplying the given equation, we get,
⇒ 3(3y + 5) = 5(3 – 7y)
⇒ 9y + 15 = 15 – 35y
⇒ 9y + 35y = 15 – 15
⇒ 44y = 0
∴ y = 0
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