Q5 of 38 Page 88

The numerator of a fraction is 3 less than its denominator. If the numerator is tripled and the denominator is increased by 2, the value of the fraction obtained is 1/2. What was the original fraction?

Let the value denominator be x

Since the numerator is 3 less than its denominator,


⇒ numerator = x-3


When numerator is tripled, new numerator = 3(x-3) = 3x-9


And, when denominator is increased by 2, new denominator = x + 2


Now it is given that,




On cross multiplying, we get,


6x – 18 = x + 2


⇒ 5x = 20


⇒ x = 4


∴Old Denominator = 4


⇒ Old Numerator = x – 3 = 1


Therefore, the original fraction was


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