Two numbers differ by 3. The sum of twice the smaller number and thrice the greater number is 19. Find the numbers.
Let the greater no. be x and smaller no. be x–3
As per given situation,
2(x–3) + 3(x) = 19
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∴ smaller no is x–3 ⇒ ![]()
Hence, The numbers are 5 and 2
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