Places A and B are 30 km apart and they are on a straight road. Hamid travels from A to B on bike. At the same time Joseph starts from B on bike, travels towards A. They meet each other after 20 minutes. If Joseph would have started from B at the same time but in the opposite direction (instead of towards A) Hamid would have caught him after 3 hours. Find the speed of Hamid and Joseph.
Let the speed of Joseph = x km/h
Let the speed of Hamid be = y km/h
When approaching each other, combined speed = ![]()
Time taken to meet = ![]()
∴ ![]()
When moving away from each other, combined speed = ![]()
Time taken for Hamid to catch up = ![]()
∴ ![]()
Equating I and II,
![]()
![]()
![]()
![]()
Substituting x=50in eq. I
![]()
![]()
![]()
Hamid's speed 50 km/hr.
Joseph's speed 40 km/hr.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
