Solve the following equations by Cramer’s method.

Let,

⇒ 3x + 3y – 24 = 2x + 4y – 28

⇒ x – y = –4 …(1)

Also,

Let

⇒ 4x + 8y – 56 = 9x – 3y

⇒ 5x –11y = – 56 …(2)

Hence the two equations are:

x – y = –4 …(1)

5x – 11y = – 56 …(2)

Now,

⇒ D = (–11 -(- 5)) = -6

Also,

D_x = 44 - 56 = -12

And,

⇒ D_y = –56 + 20 = – 36

Now, 

And, 

Hence, (2, 6) is the solution