Q2 of 17 Page 290

Construct PQR in which QR = 8 cm, ∠Q = 60° and PQ - PR = 3.5 cm.

Given: Base QR = 8 cm, PQ-PR = 3.5cm and

∠Q = 60° of Δ PQR.


Required: To construct a triangle PQR.


Steps of construction:


Step 1: Draw a segment QR of length 8cm.



Step 2: Draw ray QL such that ∠Q = 60°



Step 3: Mark an arc on opposite ray QL i.e. QS cutting at D such that QD = 3.5cm.



Step 4: Draw segment RD.



Step 5: Construct the perpendicular bisector of segment RD.



Step 6: Name the point of intersection of ray QL and the perpendicular bisector of RD as P.



Step 7: Draw segment PR.



ΔPQR is the required triangle.


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