Construct a right triangle whose base is 7.5cm. and sum of its hypotenuse and other side is 15cm.

Given base(BC) = 7.5cm and AB + AC = 15cm and ∠B = 90°

Steps of construction:

Step 1: Draw the base BC = 7.5cm

Step 2: Make an ∠XBC = 90° at the point B of base BC.

Step 3: Cut the line segment BD equals to AB + AC i.e. 15cm from the ray

XB.

Step 4: Join DC and make an angle bisector of ∠DCB.

Step 5: Let Y intersect BX at A.

Thus, ΔABC is the required triangle.